functionp - determine whether or not a given variable is a function pointer int functionp( mixed arg ); Return nonzero if `arg' is a function pointer and zero (0) otherwise. Function pointers are variables of type 'function' as indicated in the documentation for the type 'function', for example: f = (: call_other, obj, func :); The return value indicates the type of function pointer using the values given in the driver include file "include/function.h".
* FP_LOCAL - lfun pointer * FP_EFUN - efun pointer * FP_SIMUL - simul pointer * FP_FUNCTIONAL - functional
These values are bit values; the following flags may be added as well:
* FP_HAS_ARGUMENTS - arguments were included in the definition * FP_OWNER_DESTED - the owner of this function pointer has been destructed * FP_NOT_BINDABLE - it isn't possible to rebind this function pointer
To test if a function variable is an efun pointer: if (functionp(f) & FP_EFUN) ... to test if it is an efun or simul_efun: if (functionp(f) & (FP_EFUN | FP_SIMUL)) ... Try (very hard) to call the function:
if (functionp(f) & FP_OWNER_DESTED) {
   if (functionp(f) & FP_NOT_BINDABLE)
       error("Function could not be rebound.\n");
   f = bind(f, this_object());
}
evaluate(f);
Tim Hollebeek Beek@ZorkMUD, Lima Bean, IdeaExchange, and elsewhere